PSLE Exam Prep

Working Backwards: The PSLE Math Strategy for Tricky Problems

When a PSLE Math problem feels stuck, working backwards from the answer often unlocks it in seconds. Learn the 4-step method with 5 worked examples.

18 April 2026 11 min read

Working Backwards: The PSLE Math Strategy for Tricky Problems

Some PSLE Math problems look impossible from the front — too many unknowns, too many steps. But flip the question around and start from the end, and the same problem becomes a five-line answer. This is “working backwards”, and it is one of the most powerful heuristics on Paper 2.

Why Working Backwards Works

In a normal math problem, you read forward: given some starting amount → something happens → find the ending amount. You solve it by walking forward, step by step.

But many PSLE Paper 2 problems are written in reverse order: they tell you the ending amount and ask you to find the starting amount. Trying to solve those forward means juggling unknowns. Working backwards turns each unknown into a number you can actually calculate.

Forward ProblemBackwards Problem
”Sarah had $360. She spent ¼ on a bag, then ⅔ of the rest on shoes. How much is left?""Sarah spent ¼ on a bag, then ⅔ of the rest on shoes. She has $90 left. How much did she start with?”
Easy: just multiplyLooks hard: but reverse it and it becomes equally easy

💡 The Mental Switch

Forward thinking asks: “What happens next?” Backwards thinking asks: “What had to be true just before this step?” Train yourself to ask the second question whenever you get stuck.


When to Use Working Backwards

Working backwards is not the right tool for every problem. Look for these five signal patterns:

SignalExample Phrase
1. Question asks for the original / starting amount”How much did he have at first?“
2. The final amount is given as a number”He had $90 left.”
3. A chain of operations happened in order”He spent… then gave… then bought…“
4. Each step depends on the remainder of the previous”Then ⅔ of what was left…“
5. Reverse arithmetic is easyThe operations can be cleanly undone

If three or more of these match, working backwards will usually be faster than algebra or guess-and-check.


The 4-Step Working Backwards Method

ℹ️ The Method

Step 1. Write the final amount as your starting point.
Step 2. Identify the last operation that happened (the one closest to the end).
Step 3. Undo that operation (multiply ↔ divide, add ↔ subtract).
Step 4. Repeat for each earlier operation, moving step by step toward the start.

The key insight: you do not need to know all the values upfront. Each backwards step gives you the next number to work with.

The “Undo” Table

Forward OperationBackwards Operation
Add nnSubtract nn
Subtract nnAdd nn
Multiply by nnDivide by nn
Divide by nnMultiply by nn
Spent ab\frac{a}{b}, kept bab\frac{b-a}{b}Divide by bab\frac{b-a}{b} to recover the previous total

That last row is the one PSLE students miss most often. We will use it in Examples 1 and 4.


Example 1: Classic Fraction Remainder

Example 1: Sarah's Shopping

Problem:

Sarah spent 14\frac{1}{4} of her money on a bag, then 23\frac{2}{3} of the remainder on shoes. She had $90 left. How much money did she have at first?

Working backwards from $90:

Step 1 (undo the shoes). She spent 23\frac{2}{3} of the remainder on shoes, so the 90left=90 left = \frac13$ of the remainder.

Remainder after the bag=90÷13=90×3=$270\text{Remainder after the bag} = 90 \div \frac{1}{3} = 90 \times 3 = \$270

Step 2 (undo the bag). She spent 14\frac{1}{4} of her original money, so 270=270 = \frac34$ of the original.

Original=270÷34=270×43=$360\text{Original} = 270 \div \frac{3}{4} = 270 \times \frac{4}{3} = \$360

Sarah had $360 at first.

💡 Notice What We Avoided

We never had to write a single equation with xx. We never had to guess. Each number we computed was a real value (not an unknown), so checking is easy: 360×34=270360 \times \frac{3}{4} = 270, and 270×13=90270 \times \frac{1}{3} = 90. ✓


Example 2: Before-After Transfer

Example 2: David's Marbles

Problem:

David gave 18 marbles to his sister. Then he lost half of what he had left. Then he bought 5 more marbles. He now has 23 marbles. How many marbles did David have at first?

Working backwards from 23 marbles:

Step 1 (undo “bought 5 more”). Subtract 5.

235=18 marbles23 - 5 = 18 \text{ marbles}

Step 2 (undo “lost half”). Half was lost, so 18 is the other half. Multiply by 2.

18×2=36 marbles18 \times 2 = 36 \text{ marbles}

Step 3 (undo “gave 18 to sister”). Add 18 back.

36+18=54 marbles36 + 18 = 54 \text{ marbles}

David had 54 marbles at first.

⚠️ The Order Matters — Reverse It Carefully

The forward order was: gave → lost → bought. The backwards order is the exact reverse: un-bought → un-lost → un-gave. Many students try to “undo” the operations in the original (forward) order — that gives the wrong answer every time.


Example 3: Money Across Three Days

Example 3: Mei's Allowance

Problem:

On Monday, Mei spent half her money on a book. On Tuesday, she spent 12onlunch.OnWednesday,shespent12 on lunch. On Wednesday, she spent \frac13 of what she had left on a notebook. She had \8 left at the end. How much money did she have on Monday morning?

Working backwards from $8:

Step 1 (undo Wednesday). She spent 13\frac{1}{3} of what she had, so $8 = 23\frac{2}{3} of what she had on Wednesday morning.

Wednesday morning=8÷23=8×32=$12\text{Wednesday morning} = 8 \div \frac{2}{3} = 8 \times \frac{3}{2} = \$12

Step 2 (undo Tuesday). Add back the $12 she spent on lunch.

12+12=$24 (this is what she had Tuesday morning)12 + 12 = \$24 \text{ (this is what she had Tuesday morning)}

Step 3 (undo Monday). She spent half her money, so $24 is the other half.

24×2=$4824 \times 2 = \$48

Mei had $48 on Monday morning.


Example 4: Multi-Stage Fraction Remainder

Example 4: Three Boxes of Cookies

Problem:

A baker sold 25\frac{2}{5} of his cookies in the morning. He sold 13\frac{1}{3} of the remainder in the afternoon. He gave 6 of what was left to his neighbour and was left with 18 cookies. How many cookies did he bake?

Working backwards from 18 cookies:

Step 1 (undo the gift). Add the 6 cookies given away.

18+6=24 cookies (after the afternoon sale)18 + 6 = 24 \text{ cookies (after the afternoon sale)}

Step 2 (undo the afternoon). He sold 13\frac{1}{3} of the remainder, so 24 = 23\frac{2}{3} of what he had after the morning.

After morning=24÷23=24×32=36 cookies\text{After morning} = 24 \div \frac{2}{3} = 24 \times \frac{3}{2} = 36 \text{ cookies}

Step 3 (undo the morning). He sold 25\frac{2}{5} of the original, so 36 = 35\frac{3}{5} of the original.

Original=36÷35=36×53=60 cookies\text{Original} = 36 \div \frac{3}{5} = 36 \times \frac{5}{3} = 60 \text{ cookies}

The baker baked 60 cookies.

Cookies Bar Model: 60 → 36 → 24 → 18Total bakedAfter morningAfter afternoonAfter gift

💡 Always Check by Going Forward

Once you have the answer, walk it through the forward direction to check. Start with 60: morning 25×60=24\frac{2}{5} \times 60 = 24 sold, leaving 36. Afternoon 13×36=12\frac{1}{3} \times 36 = 12 sold, leaving 24. Gave away 6, leaving 18. ✓ Matches the question — the answer is correct.


Example 5: A “Doubled Plus” Pattern

Example 5: Three Stalls

Problem:

Mr Lim went to a market with some money. At the first stall, he spent half his money plus 4.Atthesecondstall,hespenthalfofwhatwasleftplus4. At the second stall, he spent half of what was left plus 4. At the third stall, he spent half of what was left plus 4.Hehad4. He had 0 left. How much money did he start with?

Working backwards from $0:

Step 1 (undo Stall 3). He spent half + $4 and ended with $0. So just before the +$4 step, he had $0 + $4 = $4. That $4 must have been the other half of what he had at Stall 3.

Before Stall 3=4×2=$8\text{Before Stall 3} = 4 \times 2 = \$8

Step 2 (undo Stall 2). Same pattern: $8 + $4 = $12, then $12 × 2 = $24.

Before Stall 2=$24\text{Before Stall 2} = \$24

Step 3 (undo Stall 1). $24 + $4 = $28, then $28 × 2 = $56.

Original amount=$56\text{Original amount} = \$56

Mr Lim started with $56.

ℹ️ Why This One Is So Hard Forward

Try solving Example 5 going forward: “Let x be his money. Then he had x24\frac{x}{2} - 4 left, then 12(x24)4\frac{1}{2}(\frac{x}{2} - 4) - 4…” You end up with nested fractions and a messy equation. Backwards, it is a string of additions and doublings — the kind of arithmetic you can do without a pencil.


When NOT to Use Working Backwards

Working backwards is powerful, but it is not always the fastest tool. Skip it when:

SituationBetter Method
The final amount is unknown (you are asked to find it)Work forward
There is only one operationJust compute directly
The problem involves two unknowns at once (e.g. before-after ratio with two people)Bar model with constant total / difference
Each step requires non-reversible operations (e.g. “rounded to the nearest 10”)Algebra or guess-and-check
Speed, distance, time problems with movementSpeed table + formula

A useful rule of thumb: if the question gives you an amount at the end and asks for an amount at the start, try working backwards first. If it gives you an amount at the start and asks for an amount at the end, work forward.


5 Common Mistakes

❌ Mistake 1: Reversing Operations in the Wrong Order

Many students undo operations in the same order they happened. They must be undone in reverse order — last operation first. Forward: A → B → C. Backwards: undo C → undo B → undo A.

❌ Mistake 2: Using Multiplication Instead of Division for Fractions

When the problem says “spent 23\frac{2}{3} of the remainder”, the amount left = 13\frac{1}{3} of that remainder. To recover the remainder, divide by 13\frac{1}{3} (or multiply by 3) — do not multiply by 23\frac{2}{3}. Many students do this in the wrong direction and get a smaller answer than the original.

❌ Mistake 3: Confusing 'Half of Total' with 'Half That Was Left'

“He spent half plus $4 at each stall” means half of what he currently had, not half of the original. The amount he had keeps shrinking, and so does each “half”. Always re-read the question to see which whole the fraction refers to.

❌ Mistake 4: Forgetting the '+/− Constant' Step

In Example 5, the operation was “spent half plus $4”. The ”+$4” must be undone (subtracted) before undoing the “half” (multiplying by 2). Skip the +$4 step and the entire chain breaks.

❌ Mistake 5: Not Checking by Going Forward

Always re-substitute your answer into the original question and walk forward. Working backwards is reliable, but a small arithmetic slip can throw the whole chain off. The forward check takes 30 seconds and catches almost all errors.


5-Day Practice Plan

Work through one type per day. Time yourself — aim for under 5 minutes per problem by Day 5.

DayFocusPractice
Day 1Single-step undo (add/subtract, multiply/divide)5 simple “started with x” problems
Day 2Two-stage fraction remainder5 problems like Example 1
Day 3Mixed operations (give away, spend, buy)5 problems like Example 2
Day 4Three-stage problems with fractions5 problems like Examples 3 & 4
Day 5Mixed exam-style + the “half plus constant” patternPast PSLE Paper 2 questions

💡 A Practice Tip Most Students Miss

After solving each problem, write the forward version of your work as a one-line check. This trains both forward and backward thinking from the same problem — and it is the easiest way to catch silly errors before the marker does.


Quick Reference Card

The 4-Step Working Backwards Method

  1. Start with the final amount given.
  2. Identify the last operation that happened.
  3. Undo it (reverse the arithmetic).
  4. Repeat — earlier operations next, in reverse order.

Operation Reversals

  • Add nn ↔ Subtract nn
  • Multiply by nn ↔ Divide by nn
  • “Spent ab\frac{a}{b}” → divide remaining amount by bab\frac{b-a}{b}
  • “Half plus nn” → subtract nn, then multiply by 2

Always check forward before moving on.


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Topics covered:

working backwards strategy PSLE Math problem solving reverse method math PSLE Math tricky problems fraction remainder backwards before after problems Singapore Math heuristics PSLE Paper 2 strategy problem solving techniques PSLE P6 Math strategy

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