O-Level Guide

Quadratic Equations: The Complete O-Level Guide (Factorise, Solve, Graph)

Master quadratic equations for O-Level Math. Learn standard form, factorisation, zero product property, and parabola graphs with worked examples.

17 March 2026 12 min read
Quadratic Equations: The Complete O-Level Guide (Factorise, Solve, Graph)

Quadratic Equations: From Zero to Hero

Every O-Level Math student needs to master quadratics. This guide takes you from recognising a quadratic equation all the way to reading its graph — with worked examples at every step.

What Is a Quadratic Equation?

A quadratic equation is any equation where the highest power of xx is 2. The standard form is:

ax2+bx+c=0ax^2 + bx + c = 0

where aa, bb, and cc are numbers and a0a \neq 0.

TermRoleExample (3x25x+2=03x^2 - 5x + 2 = 0)
aaCoefficient of x2x^2a=3a = 3
bbCoefficient of xxb=5b = -5
ccConstant termc=2c = 2

💡 Quick Check

If a=0a = 0, the x2x^2 term disappears and you’re left with a linear equation. Not quadratic!

Is It Quadratic? Three Quick Tests

EquationQuadratic?Why?
5x2+2x=05x^2 + 2x = 0YesHighest power is x2x^2, a=50a = 5 \neq 0
x34x+1=0x^3 - 4x + 1 = 0NoHighest power is x3x^3 (cubic)
x(x3)=x2+5x(x - 3) = x^2 + 5NoExpand: x23x=x2+53x5=0x^2 - 3x = x^2 + 5 \Rightarrow -3x - 5 = 0 (the x2x^2 cancels — linear!)

Step 1: Get Into Standard Form

Before you can solve, rearrange everything so the right side equals zero.

Example 1: Rearranging to Standard Form

Problem:

Write x(x+7)=18x(x + 7) = 18 in standard form.

Step 1: Expand the left side. x2+7x=18x^2 + 7x = 18

Step 2: Move 18 to the left by subtracting 18 from both sides. x2+7x18=0x^2 + 7x - 18 = 0

Answer: a=1a = 1, b=7b = 7, c=18c = -18.

Example 2: Terms on Both Sides

Problem:

Write 4x22x=5x+94x^2 - 2x = 5x + 9 in standard form.

Step 1: Move 5x5x and 99 to the left side. 4x22x5x9=04x^2 - 2x - 5x - 9 = 0

Step 2: Combine like terms (2x5x=7x-2x - 5x = -7x). 4x27x9=04x^2 - 7x - 9 = 0


Step 2: Factorise the Quadratic

Factorisation turns ax2+bx+cax^2 + bx + c into a product of two brackets. This is the skill O-Level examiners test most often.

When a=1a = 1: The Factor-Pair Method

For x2+bx+cx^2 + bx + c, find two numbers that:

  • Multiply to give cc
  • Add to give bb

Example 3: Both Numbers Positive

Factorise:

x2+10x+24x^2 + 10x + 24

We need two numbers that multiply to 24 and add to 10.

Factor pairSum
1 and 2425
2 and 1214
3 and 811
4 and 610

x2+10x+24=(x+4)(x+6)x^2 + 10x + 24 = (x + 4)(x + 6)

Example 4: One Positive, One Negative

Factorise:

x2+3x18x^2 + 3x - 18

We need two numbers that multiply to 18-18 and add to 33.

Since the product is negative, one number must be positive and the other negative. Since the sum is positive, the bigger number is positive.

Factor pairSum
6 and 3-33

x2+3x18=(x+6)(x3)x^2 + 3x - 18 = (x + 6)(x - 3)

Sign Rules Cheat Sheet

cc (constant)bb (middle term)Signs in brackets
Positive (+)(+)Positive (+)(+)Both positive: (x+_)(x+_)(x + \_)(x + \_)
Positive (+)(+)Negative ()(-)Both negative: (x_)(x_)(x - \_)(x - \_)
Negative ()(-)Positive (+)(+)Bigger is positive: (x+_)(x_)(x + \_)(x - \_)
Negative ()(-)Negative ()(-)Bigger is negative: (x_)(x+_)(x - \_)(x + \_)

Special Case: Difference of Two Squares

When there’s no middle term (b=0b = 0) and cc is negative:

x249=(x+7)(x7)x^2 - 49 = (x + 7)(x - 7)

The formula is: a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b)

When a1a \neq 1: The Cross Method

For expressions like 2x2+5x+32x^2 + 5x + 3, the factor-pair method gets trickier. Use the cross method (also called the “cross-multiplication” or “AC method”).

Use the interactive tool below to see the cross method in action:

Quadratic Factorizer

Enter coefficients to factor ax² + bx + c into (px + r)(qx + s)

+
x
+

💡 Cross Method Steps

For ax2+bx+cax^2 + bx + c:

  1. Find two numbers that multiply to a×ca \times c and add to bb.
  2. Split the middle term using these two numbers.
  3. Factor by grouping.

Example: 2x2+5x+32x^2 + 5x + 3

  • a×c=2×3=6a \times c = 2 \times 3 = 6
  • Two numbers that multiply to 6 and add to 5: 2 and 3
  • Split: 2x2+2x+3x+32x^2 + 2x + 3x + 3
  • Group: 2x(x+1)+3(x+1)2x(x + 1) + 3(x + 1)
  • Factor: (2x+3)(x+1)(2x + 3)(x + 1)

Step 3: Solve Using the Zero Product Property

Once you’ve factorised, solving is easy thanks to this rule:

If A×B=0A \times B = 0, then either A=0A = 0 or B=0B = 0 (or both).

Example 5: Full Solve

Solve:

x28x+15=0x^2 - 8x + 15 = 0

Step 1: Factorise. Find two numbers that multiply to 15 and add to 8-8.

The numbers are 3-3 and 5-5. (x3)(x5)=0(x - 3)(x - 5) = 0

Step 2: Apply Zero Product Property.

Either x3=0x - 3 = 0 or x5=0x - 5 = 0

x=3orx=5x = 3 \quad \text{or} \quad x = 5

Step 3: Check. Substitute x=3x = 3: 924+15=09 - 24 + 15 = 0

Example 6: Solve with Common Factor

Solve:

3x212x=03x^2 - 12x = 0

Step 1: Take out the common factor of 3x3x. 3x(x4)=03x(x - 4) = 0

Step 2: Apply Zero Product Property.

Either 3x=03x = 0 or x4=0x - 4 = 0 x=0orx=4x = 0 \quad \text{or} \quad x = 4

⚠️ Never Divide by x!

In Example 6, some students are tempted to divide both sides by xx. Don’t! You’ll lose the solution x=0x = 0. Always factorise first.


Step 4: The Simpler Case — x2=kx^2 = k

Some quadratics don’t need factorisation at all. If you can isolate x2x^2, just take the square root.

Example 7: Solving x² = k

Solve:

5x2=455x^2 = 45

Step 1: Divide both sides by 5. x2=9x^2 = 9

Step 2: Take the square root of both sides. x=±9=±3x = \pm\sqrt{9} = \pm 3

Answer: x=3x = 3 or x=3x = -3

❌ Don't Forget the ±

The most common mistake here is writing x=3x = 3 and forgetting x=3x = -3. Both 32=93^2 = 9 and (3)2=9(-3)^2 = 9. Always write ±\pm when you take the square root!

What if x2=16x^2 = -16? No real solution — you can’t square a real number and get a negative result. The graph of y=x2+16y = x^2 + 16 never touches the xx-axis.


Step 5: Read the Graph (Parabola Basics)

Every quadratic equation y=ax2+bx+cy = ax^2 + bx + c produces a parabola when graphed. Here’s what to look for:

Shape: Is It Smiling or Frowning?

Value of aaShapeDescription
a>0a > 0U-shape (smile)Opens upward — has a minimum point
a<0a < 0∩-shape (frown)Opens downward — has a maximum point

Key Features of a Parabola

FeatureWhat It IsHow to Find It
yy-interceptWhere the curve crosses the yy-axisSet x=0x = 0: it’s just cc
xx-intercepts (roots)Where the curve crosses the xx-axisSolve ax2+bx+c=0ax^2 + bx + c = 0
VertexThe turning point (min or max)x=b2ax = -\frac{b}{2a}, then find yy
Axis of symmetryThe vertical line through the vertexx=b2ax = -\frac{b}{2a}

How Many Roots?

The graph tells you how many solutions the equation ax2+bx+c=0ax^2 + bx + c = 0 has:

Graph Crosses xx-axis…Number of Real RootsDiscriminant (b24acb^2 - 4ac)
Twice2 distinct roots>0> 0
Once (touches)1 repeated root=0= 0
Never0 real roots<0< 0

💡 Exam Shortcut: The Discriminant

You can quickly check the number of roots without graphing by calculating b24acb^2 - 4ac.

For x28x+15=0x^2 - 8x + 15 = 0: (8)24(1)(15)=6460=4>0(-8)^2 - 4(1)(15) = 64 - 60 = 4 > 02 roots


The 5 Most Common Quadratic Mistakes

#MistakeExampleFix
1Forgetting ±\pm with square rootsWriting x=3x = 3 instead of x=±3x = \pm 3Always write ±\pm when taking \sqrt{}
2Dividing by xx instead of factorisingLosing the x=0x = 0 solutionFactor out xx first, then use Zero Product Property
3Wrong signs in factor pairs(x+3)(x+5)(x + 3)(x + 5) instead of (x3)(x5)(x - 3)(x - 5)Use the sign rules cheat sheet above
4Not rearranging to standard formTrying to factorise x2+3x=10x^2 + 3x = 10 directlyMove everything to one side: x2+3x10=0x^2 + 3x - 10 = 0
5Forgetting to check solutionsAccepting answers that don’t satisfy the original equationSubstitute each answer back into the original equation

Complete Worked Example: Putting It All Together

Full O-Level Style Question

Problem:

The area of a rectangle is 40 cm240 \text{ cm}^2. The length is 3 cm3 \text{ cm} more than the width. Find the dimensions of the rectangle.

Step 1: Set up the equation.

Let the width be xx cm. Then the length is (x+3)(x + 3) cm.

x(x+3)=40x(x + 3) = 40

Step 2: Rearrange to standard form. x2+3x=40x^2 + 3x = 40 x2+3x40=0x^2 + 3x - 40 = 0

Step 3: Factorise.

Find two numbers that multiply to 40-40 and add to 33: that’s 88 and 5-5. (x+8)(x5)=0(x + 8)(x - 5) = 0

Step 4: Solve. x=8orx=5x = -8 \quad \text{or} \quad x = 5

Step 5: Interpret.

Since width cannot be negative, x=5x = 5 cm.

Length =5+3=8= 5 + 3 = 8 cm.

Answer: Width = 5 cm, Length = 8 cm.


Quick Reference: The Complete Method

  1. Rearrange to standard form: ax2+bx+c=0ax^2 + bx + c = 0
  2. Factorise the expression (factor pairs, cross method, or difference of squares)
  3. Apply Zero Product Property: set each bracket =0= 0
  4. Solve each mini-equation for xx
  5. Check by substituting back into the original equation
  6. Reject solutions that don’t make sense in context (e.g., negative lengths)

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Topics covered:

quadratic equations O-Level Math quadratics factorise quadratic zero product property parabola graph Singapore Math Secondary 2 ax2 + bx + c quadratic formula solving quadratic equations cross method factorisation

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