PSLE Guide

PSLE Algebra: The Complete Guide for P6 Students

Master algebraic expressions, simplifying like terms, and solving equations with worked examples and visual explanations.

21 January 2026 10 min read
PSLE Algebra: The Complete Guide for P6 Students

PSLE Algebra: The Complete Guide for P6 Students

Algebra might look intimidating with all those letters, but it’s really just math with mystery boxes! Learn how to write, simplify, and solve algebraic expressions step by step.

Why Algebra Matters for PSLE

Algebra is one of the most important topics in P6 Mathematics. It appears in both Paper 1 (multiple choice and short answer) and Paper 2 (word problems). Once you understand the basics, you’ll see that algebra is a powerful tool that makes solving problems easier, not harder!

What Is a Variable?

A variable is a letter (like xx, yy, nn, or pp) that represents an unknown number. Think of it as a mystery box that could contain any number!

Example: “Maya has some stickers. We use x to represent the number of stickers.”

Here, x could be 5, or 10, or 100 - we don’t know yet!

💡 Remember

Variables are letters that represent unknown numbers. Common variables in PSLE are: nn, xx, yy, pp, mm, kk

Writing Algebraic Expressions

An algebraic expression combines variables, numbers, and operations (+, -, ×, ÷).

Addition Expressions

When we add a number to a variable:

Example: Addition

Problem:

Ahmad has pp pencils. His teacher gives him 3 more pencils. Write an expression for the total number of pencils.

Ahmad starts with pp pencils

He gets 3 more: p+3p + 3

Answer: p+3p + 3

Subtraction Expressions

⚠️ Order Matters in Subtraction!

"p5p - 5" means “start with pp and take away 5”. This is different from "5p5 - p"!

Example: Subtraction

Problem:

Mary had 20 apples at first. She gave away jj apples. How many apples does Mary have left?

Mary started with 20 apples (a known number)

She gave away jj apples: 20j20 - j

Answer: (20j)(20 - j) apples

Tricky Phrases to Watch Out For

PhraseCorrect Expression
”15 less than ddd15d - 15 (NOT 15d15 - d)
“Subtract cc from 25”25c25 - c (NOT c25c - 25)
rr years ago, he was…”Current age r- r

Multiplication Expressions

In algebra, we write multiplication without the × sign:

  • 4×m4 \times m is written as 4m4m
  • The number always goes before the letter

Example: Multiplication

Problem:

Leila has qq stickers. Siti has 5 times as many stickers as Leila. How many stickers does Siti have?

“5 times as many” means multiply by 5

Siti has: 5×q=5q5 \times q = 5q

Answer: 5q5q stickers

Division Expressions

Division is written as a fraction:

  • y÷6y \div 6 is written as y6\frac{y}{6}

Example: Division

Problem:

$p is shared equally among 3 children. How much does each child get?

Sharing equally means division

Each child gets: p÷3=p3p \div 3 = \frac{p}{3}

Answer: p3\frac{p}{3} each

Simplifying Expressions: Like Terms

What Are Like Terms?

Like terms have the same variable. Unlike terms have different variables.

Like Terms (Can Combine)

3y3y and 5y5y - both have yy

2m2m and 9m9m - both have mm

Unlike Terms (Cannot Combine)

4x4x and 7y7y - different variables

6a6a and 6b6b - different variables

❌ Common Mistake

3x+2y5xy3x + 2y \neq 5xy. Unlike terms cannot be combined! The answer stays as 3x+2y3x + 2y.

Adding Like Terms

To add like terms, add the coefficients (numbers in front) and keep the variable:

6y+2y=8y6y + 2y = 8y (because 6+2=86 + 2 = 8)

💡 Remember

A variable by itself means coefficient of 1. So a=1aa = 1a, and 4a+a=4a+1a=5a4a + a = 4a + 1a = 5a

Subtracting Like Terms

Same principle - subtract the coefficients:

10x3x=7x10x - 3x = 7x (because 103=710 - 3 = 7)

Example: Simplifying Mixed Expressions

Simplify:

6y+2+2y+56y + 2 + 2y + 5

Step 1: Group like terms

Variable terms: 6y+2y6y + 2y

Constant terms: 2+52 + 5

Step 2: Simplify each group

6y+2y=8y6y + 2y = 8y

2+5=72 + 5 = 7

Answer: 8y+78y + 7

Evaluating Expressions (Substitution)

Substitution means replacing a variable with a number and calculating the answer.

Example: Simple Substitution

If x=15x = 15, find the value of 4x+94x + 9.

4x+94x + 9

=4×15+9= 4 \times 15 + 9 (do multiplication first!)

=60+9= 60 + 9

=69= 69

⚠️ Order of Operations

Always do multiplication and division BEFORE addition and subtraction!

Solving Equations

An equation has an equals sign and tells us two things are equal. Solving an equation means finding what value makes it true.

The Balance Scale Concept

Think of an equation like a balance scale - both sides must be equal!

x + 3 = 10
x + 310✓ Balanced
Whatever we do to one side, we must do to the other to keep it balanced

Inverse Operations

To solve equations, use inverse operations (opposite operations):

  • To undo addition, use subtraction
  • To undo subtraction, use addition
  • To undo multiplication, use division
  • To undo division, use multiplication

Example: One-Step Equation (Addition)

Solve: 7+j=187 + j = 18

7 + j18✓ Balanced
To find j, subtract 7 from both sides

7+j=187 + j = 18

j=187j = 18 - 7 (subtract 7 from both sides)

j=11j = 11

Check: 7+11=187 + 11 = 18

Example: One-Step Equation (Multiplication)

Solve: 9g=729g = 72

9g72✓ Balanced
9 groups of g equals 72. Divide both sides by 9.

9g=729g = 72

g=72÷9g = 72 \div 9 (divide both sides by 9)

g=8g = 8

Check: 9×8=729 \times 8 = 72

Multi-Step Equations

For two-step equations, follow this order:

  1. First, deal with addition/subtraction (isolate the variable term)
  2. Then, deal with multiplication/division (find 1 unit)

Example: Two-Step Equation

Solve: 2x+14=702x + 14 = 70

Step 1: Subtract 14 from both sides

2x+14=702x + 14 = 70

2x=70142x = 70 - 14

2x=562x = 56

Step 2: Divide both sides by 2

x=56÷2x = 56 \div 2

x=28x = 28

Check: 2(28)+14=56+14=702(28) + 14 = 56 + 14 = 70

Word Problems with Algebra

The most challenging PSLE algebra questions are word problems. Here’s a systematic approach:

  1. Define the variable: What does xx (or nn) represent?
  2. Write expressions: Translate the words into algebra
  3. Set up the equation: What equals what?
  4. Solve step by step
  5. Answer in context: Include units and check!

PSLE-Style Word Problem

Problem:

There are 70 children playing table tennis or badminton in a sports hall. There are xx children playing table tennis. There are 14 more children playing badminton than table tennis. How many children are playing table tennis?

Step 1: Define variables

Table tennis = xx children

Badminton = x+14x + 14 children (14 more)

Step 2: Write equation

Total: x+(x+14)=70x + (x + 14) = 70

Step 3: Solve

2x+14=702x + 14 = 70

2x=7014=562x = 70 - 14 = 56

x=56÷2=28x = 56 \div 2 = 28

Answer: 28 children are playing table tennis

Check: 28+(28+14)=28+42=7028 + (28 + 14) = 28 + 42 = 70

Common Mistakes to Avoid

❌ Mistake 1: Writing m × 8 Instead of 8m

In algebra, the number goes BEFORE the letter: write 8m8m, not m8m8 or m×8m \times 8

❌ Mistake 2: Adding Unlike Terms

3x+2y3x + 2y cannot be simplified! They are unlike terms. It is NOT 5xy5xy.

❌ Mistake 3: Wrong Order in Subtraction

“15 less than dd” is d15d - 15, NOT 15d15 - d. Read carefully!

❌ Mistake 4: Forgetting to Check

Always substitute your answer back into the original equation to verify!

Quick Reference

OperationAlgebraic FormExample
Addn+5n + 5”5 more than nn
Subtractn5n - 5”5 less than nn
Multiply5n5n”5 times nn
Dividen5\frac{n}{5}nn divided by 5”
Simplify3x+2x=5x3x + 2x = 5xCombine like terms
Solvex+5=12x=7x + 5 = 12 \Rightarrow x = 7Inverse operations

Ready to Practice Algebra?

Master algebraic expressions and equations with our AI-powered math tutor that adapts to your learning pace.

Start Practicing Now →

Topics covered:

PSLE algebra P6 math algebraic expressions variables like terms solving equations Singapore math bar model algebra

Want personalized AI tutoring?

Get step-by-step help with practice problems and instant feedback.

Sign up for free