O-Level Guide

Direct & Inverse Proportion: The Complete O-Level Guide

Master direct and inverse proportion for O-Level Math. Learn y = kx, y = k/x, graphs, squared relationships, and avoid the 5 traps that cost marks.

28 March 2026 10 min read

Direct & Inverse Proportion: The Complete O-Level Guide

“y is directly proportional to x” — six words that appear in almost every O-Level Math paper. This guide breaks down both direct and inverse proportion with clear formulas, graphs, and 10 worked examples so you never lose marks on proportion questions again.

The Big Idea: What Is Proportion?

Proportion describes a predictable relationship between two quantities. When one changes, the other changes in a consistent way.

There are two types:

TypeWhat HappensKey TestEquation
DirectBoth increase (or decrease) togetherRatio y/xy/x is constanty=kxy = kx
InverseOne increases, the other decreasesProduct xyxy is constanty=k/xy = k/x

The number kk is called the constant of proportionality — it’s the glue that holds the relationship together.


Part 1: Direct Proportion

What Does “Directly Proportional” Mean?

When yy is directly proportional to xx (written yxy \propto x), it means:

  • Double xxyy doubles
  • Triple xxyy triples
  • Halve xxyy halves

The ratio yx\frac{y}{x} stays the same no matter what values you pick.

💡 The Ratio Test for Direct Proportion

Calculate y÷xy \div x for every pair of values. If you get the same number every time, the relationship is direct proportion. That number is kk.


How to Recognize Direct Proportion

Example 1: Is This Direct Proportion?

Problem:

A car travels at constant speed. Is the distance directly proportional to time?

Time (xx hours)123
Distance (yy km)204060

Check the ratio y/xy/x:

201=20,402=20,603=20\frac{20}{1} = 20, \quad \frac{40}{2} = 20, \quad \frac{60}{3} = 20

The ratio is constant (k=20k = 20), so yes — distance is directly proportional to time.

Equation: y=20xy = 20x

Example 2: NOT Direct Proportion

Problem:

A delivery service charges a fee per package plus a fixed service charge. Is the cost directly proportional to the number of packages?

Packages (xx)123
Total Cost (yy dollars)254055

Check the ratio y/xy/x:

251=25,402=20,55318.3\frac{25}{1} = 25, \quad \frac{40}{2} = 20, \quad \frac{55}{3} \approx 18.3

The ratio is NOT constant (25 ≠ 20 ≠ 18.3), so this is not direct proportion.

The fixed service charge ($10) breaks the proportionality.


The 3-Step Method: Finding the Equation

Every direct proportion exam question follows this pattern:

Step 1: Write y=kxy = kx

Step 2: Substitute known values to find kk

Step 3: Write the final equation and solve

Example 3: Finding the Equation (y = kx)

Problem:

The resistance RR (Ohms) of a wire is directly proportional to its length LL (meters). A wire of length 4 m has a resistance of 10 Ohms. (i) Find the equation connecting RR and LL. (ii) Find the resistance when L=12L = 12 m.

Step 1: Since RLR \propto L, we write R=kLR = kL.

Step 2: Substitute R=10R = 10 and L=4L = 4:

10=k×4    k=104=2.510 = k \times 4 \implies k = \frac{10}{4} = 2.5

Step 3: The equation is R=2.5LR = 2.5L.

(ii) When L=12L = 12:

R=2.5×12=30 OhmsR = 2.5 \times 12 = 30 \text{ Ohms}

Answer: (i) R=2.5LR = 2.5L (ii) R=30R = 30 Ohms


Graphs of Direct Proportion

The graph of y=kxy = kx is always a straight line through the origin (0, 0).

FeatureWhat to Look For
ShapeStraight line
Passes throughOrigin (0, 0) — always
GradientEqual to kk (the constant of proportionality)
Steeper lineLarger kk value

⚠️ The Origin Rule

If a straight-line graph does NOT pass through (0, 0), it is NOT direct proportion — even if it looks like one. A line like y=2x+3y = 2x + 3 has a y-intercept of 3, so it’s not proportional.


Direct Proportion with Squares: yx2y \propto x^2

Sometimes yy is proportional to the square of xx, not xx itself.

yx2    y=kx2y \propto x^2 \implies y = kx^2

Example 4: y Proportional to x Squared

Problem:

The kinetic energy EE (Joules) is directly proportional to the square of velocity vv (m/s). When v=2v = 2 m/s, E=12E = 12 J. Find EE when v=5v = 5 m/s.

Step 1: Ev2E \propto v^2, so E=kv2E = kv^2.

Step 2: Substitute E=12E = 12 and v=2v = 2:

12=k×22=4k    k=312 = k \times 2^2 = 4k \implies k = 3

Step 3: Equation: E=3v2E = 3v^2

When v=5v = 5:

E=3×52=3×25=75 JE = 3 \times 5^2 = 3 \times 25 = 75 \text{ J}

Answer: E=75E = 75 J

💡 Key Difference: y = kx vs y = kx²

For y=kxy = kx: double xx → double yy.
For y=kx2y = kx^2: double xxquadruple yy (because 22=42^2 = 4).


Part 2: Inverse Proportion

What Does “Inversely Proportional” Mean?

When yy is inversely proportional to xx (written y1xy \propto \frac{1}{x}), it means:

  • Double xxyy halves
  • Triple xxyy becomes one-third
  • Halve xxyy doubles

The product x×yx \times y stays the same no matter what values you pick.

💡 The Product Test for Inverse Proportion

Calculate x×yx \times y for every pair of values. If you get the same number every time, the relationship is inverse proportion. That number is kk.


How to Recognize Inverse Proportion

Example 5: Verifying Inverse Proportion

Problem:

The time to fill a tank depends on how many taps are used. Is the time inversely proportional to the number of taps?

Taps (xx)10203060
Time (yy hours)12642

Check the product x×yx \times y:

10×12=120,20×6=120,30×4=120,60×2=12010 \times 12 = 120, \quad 20 \times 6 = 120, \quad 30 \times 4 = 120, \quad 60 \times 2 = 120

The product is constant (k=120k = 120), so yes — time is inversely proportional to the number of taps.

Equation: y=120xy = \frac{120}{x}


The 3-Step Method for Inverse Proportion

Same structure, different equation:

Step 1: Write y=kxy = \frac{k}{x} (or equivalently, xy=kxy = k)

Step 2: Substitute known values to find kk

Step 3: Write the final equation and solve

Example 6: Finding the Equation (y = k/x)

Problem:

The number of days DD to build a road is inversely proportional to the number of workers WW. If 16 workers take 15 days, how many days would 20 workers take?

Step 1: D1WD \propto \frac{1}{W}, so D=kWD = \frac{k}{W}.

Step 2: Substitute D=15D = 15 and W=16W = 16:

15=k16    k=15×16=24015 = \frac{k}{16} \implies k = 15 \times 16 = 240

Step 3: Equation: D=240WD = \frac{240}{W}

When W=20W = 20:

D=24020=12 daysD = \frac{240}{20} = 12 \text{ days}

Check: More workers → fewer days. 20 > 16 and 12 < 15. ✓

Answer: 20 workers would take 12 days.

Example 7: Two-Part Inverse Proportion

Problem:

The frequency ff (Hz) of a vibrating string is inversely proportional to its length LL (cm). A string of length 60 cm vibrates at 400 Hz. (i) Find the equation. (ii) What length gives a frequency of 500 Hz?

Step 1: f=kLf = \frac{k}{L}

Step 2: 400=k60    k=24000400 = \frac{k}{60} \implies k = 24000

Step 3: f=24000Lf = \frac{24000}{L}

(ii) When f=500f = 500:

500=24000L    L=24000500=48 cm500 = \frac{24000}{L} \implies L = \frac{24000}{500} = 48 \text{ cm}

Answer: (i) f=24000Lf = \frac{24000}{L} (ii) L=48L = 48 cm


Graphs of Inverse Proportion

The graph of y=kxy = \frac{k}{x} is a curve called a hyperbola.

FeatureWhat to Look For
ShapeSmooth curve (NOT a straight line)
Passes through origin?No — never
Approaches axesGets closer and closer but never touches (asymptotes)
As xx increasesyy decreases toward zero

💡 Graph Comparison

Direct proportion → straight line through (0, 0)
Inverse proportion → curved hyperbola that never touches the axes


Inverse Square: y1x2y \propto \frac{1}{x^2}

Just like direct proportion has yx2y \propto x^2, inverse proportion has y1x2y \propto \frac{1}{x^2}.

y1x2    y=kx2y \propto \frac{1}{x^2} \implies y = \frac{k}{x^2}

Example 8: Inverse Square Relationship

Problem:

The light intensity II (lux) is inversely proportional to the square of the distance dd (meters) from a light source. At d=2d = 2 m, I=500I = 500 lux. Find II when d=5d = 5 m.

Step 1: I1d2I \propto \frac{1}{d^2}, so I=kd2I = \frac{k}{d^2}.

Step 2: Substitute I=500I = 500 and d=2d = 2:

500=k22=k4    k=2000500 = \frac{k}{2^2} = \frac{k}{4} \implies k = 2000

Step 3: Equation: I=2000d2I = \frac{2000}{d^2}

When d=5d = 5:

I=200052=200025=80 luxI = \frac{2000}{5^2} = \frac{2000}{25} = 80 \text{ lux}

Answer: I=80I = 80 lux

💡 Key Difference: y = k/x vs y = k/x²

For y=k/xy = k/x: double xx → halve yy.
For y=k/x2y = k/x^2: double xxyy becomes one-quarter (because 1/22=1/41/2^2 = 1/4).


Part 3: The Unitary Method (Quick Shortcut)

For simple problems, you can skip the equation and use the unitary method: find the value for 1 unit, then scale.

Example 9: Unitary Method

Problem:

8 workers assemble 200 components in a day. How many components can 13 workers assemble?

Step 1: Find the rate for 1 worker:

200÷8=25 components per worker200 \div 8 = 25 \text{ components per worker}

Step 2: Scale up to 13 workers:

25×13=325 components25 \times 13 = 325 \text{ components}

Answer: 13 workers can assemble 325 components.


Part 4: Direct vs Inverse — How to Tell

This is a common exam question: given a scenario, identify which type of proportion applies.

ScenarioTypeWhy
More workers → less timeInverseProduct (workers × time) is constant
More hours → more distanceDirectRatio (distance/hours) is constant
More taps → less time to fillInverseProduct (taps × time) is constant
More fabric → more costDirectRatio (cost/fabric) is constant
Faster speed → less timeInverseProduct (speed × time) = distance
More people sharing → less eachInverseProduct (people × share) is constant

💡 Quick Decision Rule

Ask yourself: “If I double one quantity, does the other double too?”
Yes → Direct proportion
No (it halves) → Inverse proportion


5 Common Mistakes That Cost Marks

Mistake 1: Using the Wrong Proportion Type

Wrong: “More workers finish faster, so time is directly proportional to workers.”

Right: More workers → less time. This is inverse proportion.

Fix: Always ask: “Do they move in the same direction or opposite?”

Mistake 2: Forgetting to Square (or Square Root)

When the question says ”yy is proportional to the square of xx,” students write y=kxy = kx instead of y=kx2y = kx^2.

Fix: Underline the exact proportionality phrase in the question before writing the equation.

Mistake 3: Mixing Up the Tests

  • Direct: check the ratio (y/xy/x = constant)
  • Inverse: check the product (x×yx \times y = constant)

Using the wrong test will give you the wrong conclusion.

Mistake 4: Writing y=kxy = kx for Inverse Proportion

The equation for inverse proportion is y=kxy = \frac{k}{x}, NOT y=kxy = kx. This mistake leads to completely wrong answers.

Mistake 5: Not Verifying Your Answer Makes Sense

After solving, do a quick sanity check:

  • Direct: if xx increased, did yy increase too?
  • Inverse: if xx increased, did yy decrease?

If your answer contradicts this, you’ve made an error somewhere.


Quick Reference Card

ConceptDirect ProportionInverse Proportion
Symbolyxy \propto xy1xy \propto \frac{1}{x}
Equationy=kxy = kxy=kxy = \frac{k}{x}
Testyx=k\frac{y}{x} = k (constant ratio)xy=kxy = k (constant product)
GraphStraight line through (0, 0)Curved hyperbola
Effect of doubling xxyy doublesyy halves
Squared versiony=kx2y = kx^2y=kx2y = \frac{k}{x^2}

💡 The One Thing to Remember

Direct = constant Ratio. Inverse = constant Product. These two tests will get you through any proportion question.


Try It Yourself

Challenge: Can You Identify and Solve?

Problem:

The pressure PP (Pa) of a gas is inversely proportional to its volume VV (cm³). When V=200V = 200 cm³, P=600P = 600 Pa. Find the pressure when the volume is compressed to 150 cm³.

Click to reveal the solution

Step 1: P1VP \propto \frac{1}{V}, so P=kVP = \frac{k}{V}.

Step 2: 600=k200    k=120,000600 = \frac{k}{200} \implies k = 120{,}000

Step 3: When V=150V = 150:

P=120,000150=800 PaP = \frac{120{,}000}{150} = 800 \text{ Pa}

Check: Volume decreased (200 → 150), so pressure should increase (600 → 800). ✓

Answer: The pressure is 800 Pa.


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Topics covered:

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